10 questions · Form 5 Physics Bab 7: Quantum Physics
According to Louis de Broglie, which physical property determines the de Broglie wavelength of a moving particle?
Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. According to Louis de Broglie, which physical property determines the de Broglie wavelength of a moving particle?
Answer: B
The de Broglie wavelength is given by λ = hp = hm × v.
2. What is the threshold frequency (f₀) of a metal?
Answer: B
Threshold frequency (f₀) is the minimum photon frequency needed to overcome the metal's work function (Φ = hf₀).
3. In a photoelectric experiment, the stopping potential V_s is measured to be 1.5 V. What is the maximum kinetic energy of the photoelectrons in Joules? (e = 1.6 × 10⁻¹⁹ C)
Answer: A
K_max = e × V_s = (1.6 × 10⁻¹⁹ C) × 1.5 V = 2.4 × 10⁻¹⁹ J.
4. What is a photon in modern quantum theory?
Answer: B
According to Max Planck and Albert Einstein, electromagnetic radiation travels in discrete energy packets called photons.
5. What happens to the stopping potential (V_s) if light of a higher frequency is used in a photoelectric setup?
Answer: B
Higher photon frequency yields higher maximum kinetic energy (K_max), requiring a larger stopping potential (e V_s = K_max) to halt emitted photoelectrons.
6. A light source emits photons with a wavelength of 400 nm. What is the momentum of each photon? (h = 6.63 × 10⁻³⁴ J s)
Answer: A
Momentum p = h / λ = 6.63 × 10⁻³⁴ J s400 × 10⁻⁹ m = 1.6575 × 10⁻²⁷ kg m s⁻¹ ≈ 1.66 × 10⁻²⁷ kg m s⁻¹.
7. Which graph correctly represents the relationship between the maximum kinetic energy (K_max) of photoelectrons and the frequency (f) of incident light?
Answer: A
From K_max = hf - hf₀, the graph of K_max vs f is a straight line y = mx + c with gradient = h and x-intercept = f₀.
8. Why could classical wave theory NOT explain the photoelectric effect?
Answer: A
Wave theory assumed energy spread continuously over wave fronts, predicting time delays for dim light, whereas experiments proved emission is instantaneous.
9. The work function of Potassium is 3.68 × 10⁻¹⁹ J. Calculate its threshold frequency f₀. (h = 6.63 × 10⁻³⁴ J s)
Answer: A
f₀ = Work Function / h = 3.68 × 10⁻¹⁹ J6.63 × 10⁻³⁴ J s = 5.55 × 10¹⁴ Hz.
10. Calculate the de Broglie wavelength of an electron moving at a velocity of 2.0 × 10⁶ m s⁻¹. (m_e = 9.1 × 10⁻³¹ kg, h = 6.63 × 10⁻³⁴ J s)
Answer: A
λ = hm × v = 6.63 × 10⁻³⁴9.1 × 10⁻³¹ × 2.0 × 10⁶ = 6.63 × 10⁻³⁴1.82 × 10⁻²⁴ = 3.64 × 10⁻¹⁰ m.