10 questions · Form 5 Physics Bab 7: Quantum Physics
10 questions · plays in fullscreen
Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. Calculate the energy of a single photon of blue light with a frequency of 6.0 × 10¹⁴ Hz. (Planck's constant h = 6.63 × 10⁻³⁴ J s)
Answer: A
E = h × f = (6.63 × 10⁻³⁴ J s) × (6.0 × 10¹⁴ Hz) = 3.978 × 10⁻¹⁹ J ≈ 3.98 × 10⁻¹⁹ J.
2. What is the gradient of a K_max against frequency (f) graph for any photoelectric metal surface?
Answer: B
Comparing K_max = hf - Φ to y = mx + c shows the gradient m equals Planck's constant h for all metals.
3. What happens to the energy of a photon when its wavelength increases?
Answer: B
From E = hc/λ, photon energy is inversely proportional to wavelength λ.
4. According to Louis de Broglie, which physical property determines the de Broglie wavelength of a moving particle?
Answer: B
The de Broglie wavelength is given by λ = hp = hm × v.
5. An electron microscope offers significantly higher magnification and resolution than an optical light microscope because:
Answer: A
High-velocity electrons have extremely small de Broglie wavelengths (~pm), drastically reducing diffraction limits and allowing ultra-high resolution.
6. Calculate the de Broglie wavelength of an electron moving at a velocity of 2.0 × 10⁶ m s⁻¹. (m_e = 9.1 × 10⁻³¹ kg, h = 6.63 × 10⁻³⁴ J s)
Answer: A
λ = hm × v = 6.63 × 10⁻³⁴9.1 × 10⁻³¹ × 2.0 × 10⁶ = 6.63 × 10⁻³⁴1.82 × 10⁻²⁴ = 3.64 × 10⁻¹⁰ m.
7. If the stopping potential for photoelectrons emitted from a metal plate is 2.0 V, what is the maximum velocity of the photoelectrons? (m_e = 9.1 × 10⁻³¹ kg, e = 1.6 × 10⁻¹⁹ C)
Answer: A
K_max = e V_s = 1.6 × 10⁻¹⁹ × 2.0 = 3.2 × 10⁻¹⁹ J. Then 0.5 × m × v² = 3.2 × 10⁻¹⁹ => v = √[ 2 × 3.2 × 10⁻¹⁹9.1 × 10⁻³¹ ] = 8.39 × 10⁵ m s⁻¹.
8. A light source emits photons with a wavelength of 400 nm. What is the momentum of each photon? (h = 6.63 × 10⁻³⁴ J s)
Answer: A
Momentum p = h / λ = 6.63 × 10⁻³⁴ J s400 × 10⁻⁹ m = 1.6575 × 10⁻²⁷ kg m s⁻¹ ≈ 1.66 × 10⁻²⁷ kg m s⁻¹.
9. What factor determines the MAXIMUM KINETIC ENERGY of photoelectrons emitted from a metal surface?
Answer: B
From Einstein's equation K_max = hf - Work Function, kinetic energy depends strictly on photon frequency f.
10. If light of frequency f below the threshold frequency (f < f₀) shines on a metal surface, what happens?
Answer: B
If f < f₀, individual photons lack sufficient energy to overcome the work function, so zero photoelectrons are emitted regardless of brightness.